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The adult population of a town in 1990 was 20440 people of which 53% were females while 60% were illiterates. Of these, the number above the age of 50 in that year was 17%. In the 2000 Census, it was found that adult population has reached 30760, 48% of them being females. Of the total adult population in 2000, 72% were below the age of 50 and total illiterates were 7000. Assume uniform pattern of age distribution amongst males and females.
If every adult female above the age of 50 was given a special annual allowance of 24000 in 1990 which was increased to 30000 by the year 2000, by what percentge has the quantum of this annual allowance increased/decreased from 1990 to 2000?
Adult females above the age of 50 in 1990 = 53% of 3474.8 = 1841.644
Total allowance given = 1842 x 24000 = 4,42,08,000
Adult females above the age of 50 in 2000 = 48% of 8612.8 = 4134
Total allowance given = 4134 x 30000 = 12,40,20,000
$$\therefore$$ Percentage increase in annual allowance from 1990 to 2000,
= $$\frac{12,40,20,000 - 4,42,08,000}{4,42,08,000} \times 100$$
= $$\frac{79812}{44208} \times 100$$
= $$180$$%
Hence, option D is the correct answer.
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