MAH MBA CET Calendars Questions

Question 1 Show answer

How many times does the 29th day of the month occur in 400 consecutive years?

A

4498

B

4497

C

4400

D

4020

E

4687

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Solution

In every year, 29th date appears 11 times i.e. in every month except February.
This will amount to 11*400 = 4400 times.
However, in every leap year, 29th date appears 1 more time in February.
So, the number of leap years:
Years divisible by 4: 400 / 4 = 100
Subtract non-leap century years (divisible by 100 but not 400): -3 (e.g., 100, 200, 300)
Total leap years = 100 - 3 = 97 occurrences.
So, total occurrences = 4400 + 97 = 4497.

Question 2 Show answer

DIRECTION for the question: Solve the following question and mark the best possible option.

If today is Thursday, then what will be the day on $$363^{rd}$$ day?

A

Thursday

B

Saturday

C

Sunday

D

Wednesday

E

Monday

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Solution

We will calculate the odd number of days i.e. remainder when 363 is divided by 7. 
The odd number of days will be 6. 
So, the day on 363rd day will be Thursday + 6 = Wednesday.

Question 3 Show answer

DIRECTION for the question: Solve the following question and mark the best possible option.

If the first day of the year (other than the leap year) was Friday, then which was the last day of that year?

A

Saturday

B

Friday

C

Monday

D

Sunday

E

Tuesday

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Solution

Last day of a non leap year = first day + 364 .
Now, we calculate the odd days which is the remainder when 364 is divided by 7 = 0.
So, the day on last day of the year = Friday + 0 = Friday.

Question 4 Show answer

DIRECTION for the question: Solve the following question and mark the best possible option.

If $$18^{th}$$ February, 1997 falls on Tuesday, then what will be the day on $$18^{th}$$ February, 1999?

A

Thursday

B

Tuesday

C

Monday

D

Friday

E

Wednesday

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Solution

We will count the number of odd days.
Odd days per year = 1 and odd days per leap year = 2.
As both 1997 and 1998 are not leap years, the number of odd days = 1 + 1 = 2.
Thus, the day on 18th Feb 1999 will be Tuesday + 2 = Thursday i.e. Option A.

Question 5 Show answer

DIRECTIONS for the question: Solve the following question and mark the best possible option.

Mrs. Susheela celebrated her wedding anniversary on Tuesday, $$30^{th}$$ September, 1997. When will she celebrate her next wedding anniversary on the same day?

A

$$30^{th}$$ September, 2002

B

$$30^{th}$$ September, 2004

C

$$30^{th}$$ September, 2003

D

$$30^{th}$$ September, 1998

E

$$30^{th}$$ October, 2003

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Solution

To celebrate her wedding on the exact same day, the year of next celebration should have either 0 or 7 or 14...odd days.
It means that if there are N days to the next day of celebration, then remainder when N is divided by 7 should be 0.
We know that every non leap year has +1 odd days and every leap year has +2 odd days.
30th Sept. 1998 --> +1
30th Sept. 1999 --> +1
30th Sept. 2000 --> +2
30th Sept. 2001 --> +1
30th Sept. 2002 --> +1
30th Sept. 2003 --> +1
Sum of all these odd days = 7 which means that day on 30th Sept. 2003 will be Tuesday + 7 = Tuesday.

Question 6 Show answer

DIRECTION for the question: Solve the following question and mark the best possible option.

Which two months in a year have the same calendar?

A

April, July

B

April, November

C

June, October

D

October, December

E

June, July