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8 years, 10 months ago
8 years, 10 months ago
Answer is d. Johan and Mary have 23 - 2x kids. Maximum value of x can be 11. Maximum Number of fights = 24C2 - xC2-( x+1)C2 -( 23-2x) C2 (every 2 kids fight)
Maximum value for number of fights is 191
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