$$\omega = \frac{1}{\sqrt{\mathrm{L}_{\mathrm{eq}} \mathrm{C}}}$$
Now for $$\mathrm{L}_{\mathrm{eq}}$$,Β assume mutual inductance is M
Let current in outer coil is $$i_1$$ and induced current in inner coil is $$i_2$$
$$V_{\text{outer}} = L_1 \frac{d i_1}{d t} + M \frac{d i_2}{d t}$$
for inner coil,Β $$0 = L_2 \frac{d i_2}{d t} + M \frac{d i_1}{d t}$$
$$V_{\text{outer}} = \left(L_1 - \frac{M^2}{L_2}\right) \frac{d i_1}{d t}$$
$$L_{\text{eq.}} = L_1 - \frac{M^2}{L_2}$$
Now,Β $$L_1 = \mu_0 n^2 s d = L$$
$$L_2 = \mu_0 (2 n)^2 \frac{s}{2} \cdot \frac{d}{2} = L$$
for $$M \rightarrow$$ $$\phi_{\text{inner}} = (\mu_0 n i) \frac{s}{2} (2 n) \frac{d}{2}$$
$$\frac{\phi}{i} = M = \frac{L}{2}$$
Now,Β $$\omega = \frac{1}{\sqrt{\mathrm{L}_{\text{eq}} \cdot \mathrm{C}}}$$
$$\omega = \frac{2}{\sqrt{3 \mathrm{LC}}}$$