Screw Gauge Measurement

Rarely Tested

$$\mathrm{Reading} = \mathrm{MSR} + (\mathrm{CSR} \times \mathrm{LC}) - \mathrm{Zero\ error}$$

MSR: Main Scale Reading, CSR: Circular Scale Reading, LC: Least Count.

Question 1

Two thin wires, Wire-1 of diameter $$0.650\,\mathrm{mm}$$ and Wire-2 of unknown diameter $$d$$ are given. To obtain the value of $$d$$, the diameters of the two wires are measured with a screw gauge. The screw gauge has a pitch of $$0.5\,\mathrm{mm}$$ and there are $$100$$ divisions on the circular scale (CS). The smallest division on the linear scale (LS) is $$0.5\,\mathrm{mm}$$. The table shows the readings of LS and CS for the measurements. The value of $$d$$ (in $$\mu\mathrm{m}$$) is:

Readings
LS (mm)CS
Wire-10.542
Wire-21.595

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