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For the following questions answer them individually
If $$a = \sqrt{9} - \sqrt{7}, b = \sqrt{7} - \sqrt{5}, C = \sqrt{11} - \sqrt{9}$$ and $$d = \sqrt{5} - \sqrt{3}$$ then
If $$56628 = 2^{B_{1}}3^{B_{2}}7^{B_{3}}11^{B_{4}}13^{B_{5}}17^{B_{6}}$$ then $$(B_{1} + B_{3} + B_{5}) - (B_{2} + B_{4} + B_{6}) =$$
The sum of all 3 digit numbers divisible by 5 is
The nearest integer to the mean proportional of 40,000 and 90,000 which when divided by each of 8, 15, 21 leaves the GCD of these numbers as remainder, is
The smallest number to be subtracted from 2305 such that the resulting number when divided by 9, 10, 15 gives the same remainder 5 in each case is
If a, b, c ∈ ℝ and $$a \neq b \neq c$$, then
$$\frac{(a - b)^{2}}{(b -a)(c - a)} + \frac{(b - c)^{2}}{(a -b)(c - a)} + \frac{(c - a)^{2}}{(a -b)(b - c)}$$
If the GCD of (p, q) = 1 and the reciprocal of the sum of the reciprocals of $$\frac{5}{7},\frac{8}{9},\frac{6}{11}$$ is $$\frac{p}{q}$$ q - 2p =
$$2\frac{2}{3} + \frac{7}{8} \div \frac{3}{4} - \frac{1}{2} \times 2\frac{1}{2} = $$
If $$l < x < m < y < n < z < t$$ then, which one of the following is true?
A person saves 20% of his monthly salary. Due to rise in the prices, his savings is decreased by 80%. If his monthly expenses after price rise are Rs, 48,000, then his annual income (in Rs.) is
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