[Download PDF] AP ICET 11th September 2020 Shift-1 Paper with Solutions

Instructions

For the following questions answer them individually

Question 81

If $$a = \sqrt{9} - \sqrt{7}, b = \sqrt{7} - \sqrt{5}, C = \sqrt{11} - \sqrt{9}$$ and $$d = \sqrt{5} - \sqrt{3}$$ then

Video Solution

Question 82

If $$56628 = 2^{B_{1}}3^{B_{2}}7^{B_{3}}11^{B_{4}}13^{B_{5}}17^{B_{6}}$$ then $$(B_{1} + B_{3} + B_{5}) - (B_{2} + B_{4} + B_{6}) =$$

Video Solution

Question 83

The sum of all 3 digit numbers divisible by 5 is

Video Solution

Question 84

The nearest integer to the mean proportional of 40,000 and 90,000 which when divided by each of 8, 15, 21 leaves the GCD of these numbers as remainder, is

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Question 85

The smallest number to be subtracted from 2305 such that the resulting number when divided by 9, 10, 15 gives the same remainder 5 in each case is

Video Solution

Question 86

If a, b, c ∈ ℝ and $$a \neq b \neq c$$, then
$$\frac{(a - b)^{2}}{(b -a)(c - a)} + \frac{(b - c)^{2}}{(a -b)(c - a)} + \frac{(c - a)^{2}}{(a -b)(b - c)}$$

Video Solution

Question 87

If the GCD of (p, q) = 1 and the reciprocal of the sum of the reciprocals of $$\frac{5}{7},\frac{8}{9},\frac{6}{11}$$ is $$\frac{p}{q}$$ q - 2p =

Video Solution

Question 88

$$2\frac{2}{3} + \frac{7}{8} \div \frac{3}{4} - \frac{1}{2} \times 2\frac{1}{2} = $$

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Question 89

If $$l < x < m < y < n < z < t$$ then, which one of the following is true?

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Question 90

A person saves 20% of his monthly salary. Due to rise in the prices, his savings is decreased by 80%. If his monthly expenses after price rise are Rs, 48,000, then his annual income (in Rs.) is

Video Solution

CAT Content

AP ICET 11th September 2020 Shift-1

If $$a = \sqrt{9} - \sqrt{7}, b = \sqrt{7} - \sqrt{5}, C = \sqrt{11} - \sqrt{9}$$ and $$d = \sqrt{5} - \sqrt{3}$$ then

If $$56628 = 2^{B_{1}}3^{B_{2}}7^{B_{3}}11^{B_{4}}13^{B_{5}}17^{B_{6}}$$ then $$(B_{1} + B_{3} + B_{5}) - (B_{2} + B_{4} + B_{6}) =$$

The sum of all 3 digit numbers divisible by 5 is

The nearest integer to the mean proportional of 40,000 and 90,000 which when divided by each of 8, 15, 21 leaves the GCD of these numbers as remainder, is

The smallest number to be subtracted from 2305 such that the resulting number when divided by 9, 10, 15 gives the same remainder 5 in each case is

If a, b, c ∈ ℝ and $$a \neq b \neq c$$, then $$\frac{(a - b)^{2}}{(b -a)(c - a)} + \frac{(b - c)^{2}}{(a -b)(c - a)} + \frac{(c - a)^{2}}{(a -b)(b - c)}$$

If the GCD of (p, q) = 1 and the reciprocal of the sum of the reciprocals of $$\frac{5}{7},\frac{8}{9},\frac{6}{11}$$ is $$\frac{p}{q}$$ q - 2p =

$$2\frac{2}{3} + \frac{7}{8} \div \frac{3}{4} - \frac{1}{2} \times 2\frac{1}{2} = $$

If $$l < x < m < y < n < z < t$$ then, which one of the following is true?

A person saves 20% of his monthly salary. Due to rise in the prices, his savings is decreased by 80%. If his monthly expenses after price rise are Rs, 48,000, then his annual income (in Rs.) is

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If a, b, c ∈ ℝ and $$a \neq b \neq c$$, then
$$\frac{(a - b)^{2}}{(b -a)(c - a)} + \frac{(b - c)^{2}}{(a -b)(c - a)} + \frac{(c - a)^{2}}{(a -b)(b - c)}$$