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n ( > 4 ) kids are standing in a line one next to the other, such that everybody is facing north. How many kids are there? Statement 1: Number of ways in which 3 kids can be selected such that no two selected kids are standing next to each other is 10. Statement 2: If the kids are made to sit around a circular table such that one particular kid always occupies a specific seat, the number of such arrangements possible is 120.
It is powerplay quesn. In this question's answer, the answer given form 1st statement is : From statement 1: Let there be n kids in the line. The number of ways of selecting 3 of them such that the selected kids are not next to each other is n−2C3=10 => n-2 = 5 => n = 7. Can you elaborate ?
If a7! + b8! + c9! + d10! = x, where a, b, c and d are natural numbers that are not multiples of 10, then how many distinct values of unit’s digit of x are possible?
I can't increase my questions attempt rate. It's below 50 always. What will i do?(any suggestion)
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How many natural numbers having less than 4 digits can be formed such that sum is less than 10?
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