Mr. Shah has to divide his assets worth rupees 30 crores in 3 parts to be given to three id his sons Ajay, Vijay and Arun ensuring that every son gets at least worth rupees 5 crores . In how many ways can this be done if it is given that three sons should get their shares in multiple of rupees 1 crore?.Please provide detailed solution

Let the shares of different sons be 5+a, 5+b, and 5+c5+a + 5+b +5+c = 30a+b+c = 15. Now we have to find non-negative integral solutions of this equation which is given by(n+r-1)C(r-1), so we get 17C2 = 136

Meujhe answers samjh me nagi aya bsdk

Please post the full question so that we can help you with the solution.

A 100 litre vessel contains water and milk in the ratio 2 : 3 and a 50 litre vessel contains water and milk in the ratio 3 : 2. If the contents of these vessels are mixed in the ratio 1 : 3 in a third vessel, what will be the respective ratio of milk to water in the third vessel? a) 12 : 13 b) 9 : 11 c) 11 : 9 d) 13 : 12

So water in the first vessel is 40 litres and milk is 60 litres.In the second vessel, water is 30 litres and milk is 20 litres.Now to mix them in ratio of 1:3, lets take capacity of vessel 3 as 400 litres.In this we have 100 litres from vessel 1 and 300 litres from vessel 2.So total milk in vessel 3 = 60 (V1) + {20 X 6} (V2) = 180 litres.Remaining is water i.e. 400 - 180 = 220 litres.Therefore ratio of milk to water in V3 is 9:11.Hence option (b) is the answer.

There are 7 boys and 8 girls in a class. A teacher has 3 items viz a pen, a pencil and an eraser, each 5 in number. He distributes the items, one to each student. What is the probability that a boy selected at random has either a pencil or an eraser?

total no. of cases is 15*15 = 225.No.of cases that one particular boy gets eraser = 5No.of cases that one particular boy gets pencil = 5therefore ans is 10/225

Will you Please explain? Shiv Parashar.

Increase in denominator,decreases the fraction value by how much percent?

Let the fraction be y/x and the denominator be increased by a%.Thus, the new fraction obtained is y/(x + x*a/100) = y/[x(1 + a/100)]The percent decrease in the original fraction = $$\frac{y/x - y/[x(1 + a/100)]}{y/x}$$x100% = $$\frac{a}{100 + a}$$x100%

There are 4 qualifying examinations to enter into Oxford University: RAT, BAT, SAT, and PAT. An Engineer cannot go to Oxford University through BAT or SAT, A CA on the other hand can go to the Oxford University through the RAT, BAT & PAT but not through SAT. Further there are 3 ways to become a CA (viz, Foundation, Inter & Final). Find the ratio of number of ways in which an Engineer can make it Oxford University to the number of ways a CA can make it to Oxford University.

The number of ways through which an engineer can make it to Oxford is through RAT and PAT i.e 2.The number of ways through which a CA can make it to Oxford is through RAT BAT and PAT i.e 3.The ratio is 2/3.