H, please check for NEET previous papers here: https://cracku.in/neet-previous-papers

After selling a certain quantity of fruits , Mohanlal realised that he was selling at a loss of 15% . He then sold the remaining fruits that he had at 20% profit such that he ended up with 0 per cent profit and 0 net loss . If he sold 40 Kg of fruits on loss , how many kgs of fruits did he sell on profit

Assume, that the quantity of fruits sold at 20% profit be x' Kg and the cost price of each fruit be '1' Rs/kg. Thus, the simple and straight forward comprehension of the question is : 40(0.85) + x(1.2) = 40+x. Thus, x = 30 kg.

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if (a+b) +1/c+d =1 and (c+d) +1/(e+f)=1 then what is the value of (a+b)(c+d)(e+f)

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if it is given that (c+d) > 0 or c,d are greater than 0, then, on adding both equations we get, (a+b)+ (1/(c+d)) +(c+d) + (1/(e+f)) = 2 and applying AM > = GM on middle 2 terms we get, (1/(c+d))+(c+d) >= 2, this implies that (a+b) and (e+f) must be 0 which means the value of (a+b)(c+d)(e+f) must be 0.<br>Hope that helps.<br>