Rajini is 7 times as oldas his son .after 3 years he will be 5 times his sons age.what is rajinis present age

rajini's age - 42. let r's age be x let sons age be y x = 7y ------------eqA after 3 years x+3=r's age , y+3= sons age x+3 = 5(y+3) x+3 = 5y +15 x= 5y +12 -------eqB by elimination, X= 42

my profile is like 7/6/7 general category fresher how much percentile i..

Hello, Saumya Srivastava Please check here: https://cracku.in/cat-percentile-required-for-iim-calls Thanks, Team Cracku.

plz provide the pdf in Hindi

Hi, As of now we are providing Banking, SSC & Railways mocks are available in Hindi & English. You need to select the language before starting the mock. For CAT exam it will be in English only. As of now previous papers are available in english and we are working on them and will be up in coming days. Thanks & Regards, Team Cracku.

My profile is like 7/7/8....how much percentile is required for BLACKI?

depends upon your category?if genral then above 96 with work ex

A bag has a total of 120 notes in denominations of ₹2,₹5and ₹10. The total value of the notes in the bag is ₹760. if there were twice as many ₹5 notes, the total value of the notes would be ₹960. Find the number of ₹10 notes in the bag

Ans:50 let 5 rupee notes be = X and 2 rupees notes be = Y equation will be 5X+2Y+(120-X-Y)10=760 ------ (1) if there were twice as many notes 5 rupees i.e. 2X notes of 5 rupees 2*5X+2Y+(120-X-Y)=960 --------(2) solve the both equations X=40 and Y=50. alternative: there is 200 rupee increase in total amount due to X 5 rupees note so, 5X=200 , X=40 after subtracting 40 from 120 note there will be 80 notes and amount will be 560 equation will be 2A+(80-A)10=560 8A=240 A=30 80-A = 80-30 = 50.

increase in Rs5 denomination notes caused an increase of Rs200 therefore , initially there must be 40 notes of Rs.5 denomination so, 760-200=560 remaining ,which is to be covered in more 80 qty of notes , the only possibility is 10*50 + rs2*30 =560 thus,50 answer