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1 year, 7 months ago
1 year, 7 months ago
increase in Rs5 denomination notes caused an increase of Rs200
therefore , initially there must be 40 notes of Rs.5 denomination
so, 760-200=560 remaining ,which is to be covered in more 80 qty of notes ,
the only possibility is 10*50 + rs2*30 =560
thus,50 answer
1 year, 7 months ago
Ans:50
let 5 rupee notes be = X
and 2 rupees notes be = Y
equation will be 5X+2Y+(120-X-Y)10=760 ------ (1)
if there were twice as many notes 5 rupees i.e. 2X notes of 5 rupees
2*5X+2Y+(120-X-Y)=960 --------(2)
solve the both equations X=40 and Y=50.
alternative: there is 200 rupee increase in total amount due to X 5 rupees note
so, 5X=200 , X=40
after subtracting 40 from 120 note there will be 80 notes and amount will be 560
equation will be 2A+(80-A)10=560 8A=240 A=30 80-A = 80-30 = 50.
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