The difference between the compound interest on a sum, at a certain rate of interest, for the first and the second year is Rs. 800. What will be the difference if the rate of interest is increased by 150%? Rs. 2000 Rs. 3000 Rs. 4000 Rs. 5000 Show Answer

Hi Let Principal be P and rate of interest be R Now Interest for 1st year will PR/100 Now interest for 2nd year will be : PR/100 +P(R/100)^2 Subtracting we get P(R/100)^2=800 Now when R is increased by 150 percent so R becomes 2.5 times its original value and R^2 will become 6.25 times its value so we get difference to be P (2.5R/100)^2 =800*6.25=5000

Let principle be P and Rate be R. On 1st yr interest is = P*R/100 On 2nd year CI is = (P*R/100)+ P*R*R/(100*100) Difference is P*R*R/(100*100) =800 Now since value of difference is directly proportional to square of rate thus when rate increase by 150% i.e 2.5 times difference increase by square of 2.5 ie 6.25 time or 6.25*800 ie 5000

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a man swims downstream distance at 45 km in 2 hr if the speed of the current is 4.5 km/h then the time taken by the man to swim the 50% more distance in upstream is

Hi Let speed of man be v Now in downstream effective speed = v+4.5 Now as per given condition : (45/v+4.5) =2 so v+4.5=22.5 so we get v=18 Now distance required to cover in upstream = 45 (1.5)=67.5 Now therefore time = (67.5/v-4.5) (In upstream effective speed is speed of man - speed of current ) solving we get 67/13.5 so time = 5 hours.