if the six digit number 479xyz is exactly divisible by 7,11and 13 then value of x,y and z is

A number is divisible by 7, 11 and 13 when 6 digit number xyzxyz , so x= 4, y= 7 and z= 9 as a result (y+z):x= 4 Ans. More detail Why & How Step 1 : The LCM of 7, 11 and 13 is 1001. Step 2 : In 6-digit number 479xyz , minimum values are x = 0, y=0 and z=0 i.e. assume the number as 479000. Step 3 : By dividing 479000 with 1001 , we get Quotient = 478 and Rremainder 522. Step 4 : (479000 - 522 = 478478 ), here 478478 is exactly divisible by 1001 , or 7, 11 and 13. But starting 3 digits are not 479. Step 5 : So quotient must be 478 + 1 = 479 Step 6 : Then required 6-digits number is the Dividend = Divisor x quotient = 1001 x 479 = 479479 Step 7 : As we get the number 479xyz = 479479, hence x= 4, y = 7 and z = 9 Step 8 : Finally (y+z):x = (7+9):4= 4 is the answer.

First, Let's find the LCM of 7,11,13. LCM=1001 assume x=y=z=0 479000/1000=478+522/1001 So we have a reminder od 522 when we divided by 1001 So, we get the nearest multiple of above this all we have to do is add the difference between 1001 and 522 1001-522=479 479000+479=479479 which we known as a multiple of 1001. So, one possible solution is xyz=479 However, we're not quite done. Any number that's divisible by 1001is divisible by 7,11,13. So if we added 1001 to this number. It will satisfy our requirements 479479+1001=480480. So the other possible solution is xyz=480 These are the only two possibilities.