In each of the following questions, one or two equations (s) is/are given. On
their basis you have to determine relation between x and y and then,
Give answer a: if x < y
Give answer b: if x > y
Give answer c: if x ≤ y
Give answer d: if x ≥ y
Give answer e: if x = y
I. $$y^{2} + 2y - 3 = 0$$
II. $$2x^{2} - 7x + 6 = 0$$
II : $$2x^2 - 7x + 6 = 0$$
=> $$2x^2 - 4x - 3x + 6 = 0$$
=> $$2x (x - 2) - 3 (x - 2) = 0$$
=> $$(2x - 3) (x - 2) = 0$$
=> $$x = \frac{3}{2} , 2$$
I : $$y^2 + 2y - 3 = 0$$
=> $$y^2 + 3y - y - 3 = 0$$
=> $$y (y + 3) - 1 (y + 3) = 0$$
=> $$(y + 3) (y - 1) = 0$$
=> $$y = -3 , 1$$
$$\therefore$$ $$x > y$$
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