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Instructions
In each of the following questions, one or two equations (s) is/are given. On
their basis you have to determine relation between x and y and then,
Give answer a: if x < y
Give answer b: if x > y
Give answer c: if x ≤ y
Give answer d: if x ≥ y
Give answer e: if x = y
Solution
I : $$2x^2 + 5x + 2 = 0$$
=> $$2x^2 + 4x + x + 2 = 0$$
=> $$2x (x + 2) + 1 (x + 2) = 0$$
=> $$(2x + 1) (x + 2) = 0$$
=> $$x = \frac{-1}{2} , -2$$
II : $$4y^2 = 1$$
=> $$y^2 = \frac{1}{4}$$
=> $$y^2 = (\pm \frac{1}{2})^2$$
=> $$y = \pm \frac{1}{2}$$
$$\therefore$$ $$x \leq y$$
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