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Pipe A fills an empty tank in 4 hours and pipe B in 6 hours. If the two pipes are opened for one hour each alternatively with pipe A being opened first, then the tank will be filled (in hours) is
$$2\frac{3}{4}$$
$$3\frac{1}{2}$$
$$4\frac{2}{3}$$
$$5\frac{1}{4}$$
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