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The sum of a number and its reciprocal is thrice the difference of the number and its reciprocal. The number is:
Let the number be a
It is given thatΒ sum of a number and its reciprocal is thrice the difference of the number and its reciprocal.
a+$$\ \frac{\ 1}{a}$$ = 3(a-$$\ \frac{\ 1}{a}$$ )
2a = $$\ \frac{\ 4}{a}$$
a = $$\ \frac{\ 2}{a}$$
$$\ \ a^2=2$$
a =Β $$\pm \surd{2}$$
A is the correct answer.
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