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The number of students who prefer beverage C is approximately what percent of the number of students who prefer beverage D?
Number of students who prefer beverage C = 4% of 6800 = $$\frac{4}{100}$$ x 6800 = 272
Number of students who prefer beverage D = 34% of 6800 = $$\frac{34}{100}$$ x 6800 = 2312
Percentage of students who prefer beverage C over D = 11.76 ≈ 12
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