We know that, $$sin(x+y) = sinxcosy + cosxsiny$$ --------(i)
and $$sin(x-y) = sinxcosy-cosxsiny$$ ------------(ii)
Subtracting equation (ii) from (i), we get :Â
$$sin(x+y) - sin(x-y) = 2cosxsiny$$ ------------(iii)
Let $$x + y = C$$ and $$x - y = D$$
=> $$x = \frac{C+D}{2}$$
and $$y = \frac{C-D}{2}$$
Substituting above values in equation (iii)
=> $$sinC - sinD = 2cos(\frac{C+D}{2})sin(\frac{C-D}{2})$$
=> Ans - (C)
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