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Instructions
For the two given equations I and II.
Give answer a: if p is greater than q.
Give answer b: if p is smaller than q.
Give answer c: if p is equal to q.
Give answer d: if p is either equal to or greater than q.
Give answer e: if p is either equal to or smaller than q.
Solution
I : $$p^2 + 5p + 6 = 0$$
=> $$p^2 + 3p + 2p + 6 = 0$$
=> $$p (p + 3) + 2 (p + 3) = 0$$
=> $$(p + 2) (p + 3) = 0$$
=> $$p = -2 , -3$$
II : $$q^2 + 3q + 2 = 0$$
=> $$q^2 + q + 2q + 2 = 0$$
=> $$q (q + 1) + 2 (q + 1) = 0$$
=> $$(q + 2) (q + 1) = 0$$
=> $$q = -2 , -1$$
$$\therefore p \leq q$$
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