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Instructions
In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer :
a:If x < y
b: If x > y
c: If x ≤ y
d: If x ≥ y
e: If relationship between x and y cannot be determined ,
Solution
I. $$6x^{2} - 19x + 15 = 0$$
=> $$6x^2 - 9x - 10x + 15 = 0$$
=> $$(3x - 5) (2x - 3) = 0$$
=> $$x = \frac{5}{3} , \frac{3}{2}$$
II. $$5y^{2} - 22y + 24 = 0$$
=> $$5y^2 - 10y - 12y + 24 = 0$$
=> $$(5y - 12) (y + 2) = 0$$
=> $$y = \frac{12}{5} , 2$$
$$\therefore y > x$$
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