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Instructions
In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer :
a:If x < y
b: If x > y
c: If x ≤ y
d: If x ≥ y
e: If relationship between x and y cannot be determined ,
Solution
I. $$4x^{2} - 12x + 5 = 0$$
=> $$4x^2 - 2x - 10x + 5 = 0$$
=> $$(2x - 5) (2x - 1) = 0$$
=> $$x = \frac{5}{2} , \frac{1}{2}$$
II. $$4y^{2} - 8y + 3 = 0$$
=> $$4y^2 - 2y - 6y + 3 = 0$$
=> $$(2y - 3) (2y - 1) = 0$$
=> $$y = \frac{3}{2} , \frac{1}{2}$$
$$\therefore$$ clearly we can see that x is greater than or equals to y
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