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Instructions
In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer :
a:If x < y
b: If x > y
c: If x ≤ y
d: If x ≥ y
e: If relationship between x and y cannot be determined ,
Solution
I. $$15x^{2} + 26x + 8 = 0$$
=> $$15x^2 + 6x + 20x + 8 = 0$$
=> $$(3x + 4) (5x + 2) = 0$$
=> $$x = \frac{-4}{3} , \frac{-2}{5}$$
II. $$25y^{2} + 15y + 2 = 0$$
=> $$25y^2 + 5y + 10y + 2 = 0$$
=> $$(5y + 2) (5y + 1) = 0$$
=> $$y = \frac{-2}{5} , \frac{-1}{5}$$
$$\therefore x \leq y$$
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