A thief is stopped by a policeman from a distance of 150 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 7 km/hr and that of policeman as 9 km/hr, how far the thief would have run, before he is over-taken by the policeman?

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 7 km/hr and speed of policeman = 9 km/hr

=> Relative speed = 9 - 7 = 2 km/hr

Distance between them = 150 metres = 0.15 km

=> Time taken = $$\frac{distance}{speed}$$

= $$\frac{0.15}{2} = \frac{3}{40}$$ hr

$$\therefore$$ Distance covered by thief before he was caught = $$7 \times \frac{3}{40}$$

= 0.525 km = 525 metres

=> Ans - (D)