Question 94

What is the simplified value of $$sin^{2}$$ (90 - θ) - [{sin(90 - θ)sin θ}/tan θ]?

Solution

Expression : $$sin^2(90^\circ-\theta)-[\frac{sin(90^\circ-\theta)sin\theta}{tan\theta}]$$

Using, $$sin(90^\circ-\theta)=cos\theta$$

= $$cos^2\theta-(\frac{cos\theta sin\theta}{tan\theta})$$

= $$cos^2\theta-(\frac{cos\theta sin\theta}{\frac{sin\theta}{cos\theta}})$$

= $$cos^2\theta-cos^2\theta=0$$

=> Ans - (C)


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