Solution
Expression : $$sin^2(90^\circ-\theta)-[\frac{sin(90^\circ-\theta)sin\theta}{tan\theta}]$$
Using, $$sin(90^\circ-\theta)=cos\theta$$
= $$cos^2\theta-(\frac{cos\theta sin\theta}{tan\theta})$$
= $$cos^2\theta-(\frac{cos\theta sin\theta}{\frac{sin\theta}{cos\theta}})$$
= $$cos^2\theta-cos^2\theta=0$$
=> Ans - (C)
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