Question 94

If secA -­ tanA = x, then the value of x is

Solution

Expression : secA -­ tanA = x

= $$\frac{1}{cosA}-\frac{sinA}{cosA}$$

= $$\frac{1-sinA}{cosA} = \frac{\sqrt{(1-sinA)^2}}{\sqrt{1-sin^2A}}$$

= $$\sqrt{\frac{(1-sinA)^2}{(1-sinA)(1+sinA)}}$$

= $$\sqrt{\frac{1-sinA}{1+sinA}}$$

=> Ans - (B)


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