If $$R_n (n \in N)$$ is a rectangle of length $$I_n = \frac{1}{n}$$, breadth $$b_n = \frac{1}{n + 1}$$, then the sum of areas of $$R_1, R_2, ........ R_{100}$$ is:

A

$$\frac{99}{100}$$

B

$$\frac{101}{100}$$

C

$$\frac{100}{101}$$

D

$$\frac{100}{99}$$