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When 40% of a number is added to 84. if the resultant is the number itself. then that number is
Let the number is x
Now, as per the condition given in the question,
$$\Rightarrow \dfrac{40x}{100}+84=x$$
$$\Rightarrow 0.4x+84=x$$
$$\Rightarrow x-0.4x=84$$
$$\Rightarrow 0.6x=84$$
$$\Rightarrow x=\dfrac{84}{0.6}=\dfrac{840}{6}=140$$
$$x=140$$
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