Question 91

If secA/√$$(sec^2A - 1)$$ = x, then value of x is

Solution

Expression : $$\frac{secA}{\sqrt{sec^2A-1}}$$

$$\because$$ $$(sec^2A-tan^2A=1)$$

= $$\frac{secA}{\sqrt{tan^2A}} = \frac{secA}{tanA}$$

= $$(\frac{1}{cosA})\div(\frac{sinA}{cosA})$$

= $$(\frac{1}{cosA})\times(\frac{cosA}{sinA})$$

= $$\frac{1}{sinA} = cosecA$$

=> Ans - (B)

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