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If S is the midpoint of a straight line PQ and R is a point different from S, such that PR=RQ, then
$$\angle PRS$$ = 90°
$$\angle QRS$$ = 90°
$$\angle PSR$$= 90°
$$\angle QSR$$ < 90°
From the given data, figure can be drawn as
Here PR = RQ, and S is the mid point of PQ
So, ∠PSR = 90°
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