A cricket ball, thrown across a field, is at heights of $$h_1$$ and $$h_2$$ above the point of projection, at time $$t_1$$ and time $$t_2$$ after the throw, respectively. It is then caught by the wicket keeper at the same height as that from which it was thrown. The Time of Flight $$T$$ of the ball is

A

$$T = \frac{h_1t_2^2 - h_2t_1^2}{h_1t_2 - h_2t_1}$$

B

$$T = \frac{h_1t_2^2 + h_2t_1^2}{h_2t_1 + h_1t_2}$$

C

$$T = \frac{h_1t_1^2 - h_2t_2^2}{h_1t_1 - h_2t_2}$$

D

$$T = \frac{h_1t_1^2 + h_2t_2^2}{h_1t_1 + h_2t_2}$$