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Polar moment of inertia of a hollow shaft having D and d as outer and inner diameters, is given by:
$$\frac{\pi}{4}(D^{4}-d^{4})$$
$$\frac{\pi}{32}(D^{4}-d^{4})$$
$$\frac{\pi}{64}(D^{4}-d^{4})$$
$$\frac{\pi}{12}(D^{4}-d^{4})$$
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