Choose the correct relation(s) from the following:
(i) $$\sqrt{6}+\sqrt{2}=\sqrt{5}+\sqrt{3}$$
(ii) $$\sqrt{6}+\sqrt{2}<\sqrt{5}+\sqrt{3}$$
(iii) $$\sqrt{6}+\sqrt{2}>\sqrt{5}+\sqrt{3}$$
$$\sqrt{2}$$ = 1.414
$$\sqrt{3}$$ = 1.732
$$\sqrt{5}$$ = 2.236
$$\sqrt{6}$$ = 2.449
=> $$\sqrt{2}$$ + $$\sqrt{6}$$ = 3.863
and $$\sqrt{5}$$ + $$\sqrt{3}$$ = 3.968
=> $$\sqrt{2}$$ + $$\sqrt{6}$$ < $$\sqrt{5}$$ + $$\sqrt{3}$$
Thus, (ii) is correct.
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