$$(16)^{\frac{-3}{4}}+2^{-3}+(8)^{\frac{-2}{3}}$$ is equivalent to
Expression : $$(16)^{\frac{-3}{4}}+2^{-3}+(8)^{\frac{-2}{3}}$$
= $$(2)^{4 \times \frac{-3}{4}} + \frac{1}{8} + (2)^{3 \times \frac{-2}{3}}$$
= $$(2)^{-3} + \frac{1}{8} + (2)^{-2}$$
= $$\frac{1}{8} + \frac{1}{8} + \frac{1}{4}$$
= $$\frac{1 + 2 + 1}{8} = \frac{4}{8}$$
= $$\frac{1}{2}$$
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