Question 87

What are the roots of the quadratic equation $$21x^{2} - 37x - 28 = 0$$ ?

Solution

Equation : $$21x^{2} - 37x - 28 = 0$$

=> $$21x^2-49x+12x-28=0$$

=> $$7x(3x-7) +4(3x-7)=0$$

=> $$(7x+4)(3x-7)=0$$

=> $$x = \frac{-4}{7} , \frac{7}{3}$$

=> Ans - (C)


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