Question 87

The respective ratio of the present ages of a mother and daughter is 7 : 1. Four years ago the respective ratio of their ages was 19:1. What will be the mother's age four years from now ?

Solution

Let the present ages of mother and daughter be x and y respectively.

$$\frac{y}{x} = \frac{1}{7}$$ => x = 7y

$$\frac{y-4}{x-4} = \frac{1}{19}$$ => 19y - 76 = x - 4 => x = 19y - 72

=> 7y = 19y - 72 => y = 6 and x = 42

Age of mother 4 years from now = 42 + 4 = 46

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