Question 86

Three numbers are in the ratio 1 : 2 : 3 and the sum of their squares is 504. The largest of the numbers is

Solution

Let the 3 numbers be a, 2a, 3a respectively.

According to the problem,

$$a^2+4a^2+9a^2=504$$

$$\Rightarrow$$ $$14a^2=504$$

$$\Rightarrow$$ $$a^2=36$$

$$\Rightarrow$$ $$a = 6$$

$$\therefore\ $$The largest of the numbers = 3a = 18

Hence, the correct answer is Option C

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