Three numbers are in the ratio 1 : 2 : 3 and the sum of their squares is 504. The largest of the numbers is
Let the 3 numbers be a, 2a, 3a respectively.
According to the problem,
$$a^2+4a^2+9a^2=504$$
$$\Rightarrow$$ย $$14a^2=504$$
$$\Rightarrow$$ ย $$a^2=36$$
$$\Rightarrow$$ย $$a = 6$$
$$\therefore\ $$The largest of the numbers = 3a = 18
Hence, the correct answer is Option C
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