The least fraction that should be added to $$3\frac{2}{3}+6\frac{7}{12}+4\frac{9}{36}+6+7+\frac{1}{2}$$ to make the sum a whole number is

A

$$\frac{17}{36}$$

B

$$\frac{5}{12}$$

C

$$\frac{1}{12}$$

D

$$\frac{5}{36}$$