Solution
Expression : $$\frac{17}{3}+[\frac{3}{2}(2x-\frac{5}{3})]=\frac{1}{6}$$
= $$\frac{17}{3}+[\frac{3}{2}(\frac{6x-5}{3})]=\frac{1}{6}$$
= $$\frac{34}{6}+(\frac{18x-15}{6})=\frac{1}{6}$$
= $$34+18x-15=1$$
= $$18x=1+15-34=-18$$
= $$x=\frac{-18}{18}=-1$$
=> Ans - (D)
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