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Given : $$ab=6$$ -----------(i)
Also, $$a+b=5$$ -----------(ii)
Cubing both sides, we get :
=> $$(a+b)^3=(5)^3$$
=> $$a^3+b^3+3ab(a+b)=125$$
Substituting values from equation (i) and (ii)
=> $$a^3+b^3+3(6)(5)=125$$
=> $$a^3+b^3=125-90=35$$
=> Ans - (C)
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