Solution
Let the fraction be $$x$$
According to ques,
=> $$x+\frac{3}{x}=\frac{37}{10}$$
=> $$\frac{x^2+3}{x}=\frac{37}{10}$$
=> $$10x^2+30=37x$$
=> $$10x^2-37x+30=0$$
=> $$10x^2-25x-12x+30=0$$
=> $$5x(2x-5)-6(2x-5)=0$$
=> $$(2x-5)(5x-6)=0$$
=> $$x=\frac{5}{2},\frac{6}{5}$$
=> Ans - (A)
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