A ball of diameter 4 cm is kept on top of a hollow cylinder standing vertically. The height of the cylinder is 3 cm, while its volume is $$9\pi$$ cubic centimeters. Then the vertical distance, in cm, of the topmost point of the ball from the base of the cylinder is
Correct Answer: 6
The volume of a cylinder is $$\pi * r^2 * 3 = 9 \pi$$
r = $$\sqrt{3}$$ cm.
Radius of the ball is 2 cm. Hence, the ball will lie on top of the cylinder.
Lets draw the figure.
Based on the Pythagoras theorem, the other leg will be 1 cm.
Thus, the height will be 3 + 1 + 2 = 6 cm
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