Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
In graphite and diamond the percentage of P-character of the hybrid orbital's in hybridization are respectively
Carbon is $$sp^2$$ hybridized in graphite, with p-character $$\frac{2}{3} \approx 67\%$$. In diamond it is $$sp^3$$, with p-character $$\frac{3}{4} = 75\%$$.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation