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When a electric current is passed though acidified water, $$112\text{ ml}$$ of $$\text{H}_2$$ gas at NTP was collated at cathode in 965 seconds. The current passed in ampheres is
$$112\text{ mL}$$ of $$\text{H}_2$$ at NTP is $$\frac{112}{22400} = 0.005$$ mol. Since $$2\text{H}^+ + 2e^- \rightarrow \text{H}_2$$, this needs $$0.01$$ mol of electrons, i.e. $$0.01 \times 96500 = 965\text{ C}$$. Current $$= \frac{965}{965} = 1\text{ A}$$.
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