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If $$x^{2}-5x-24=0$$, then find the value of x
+8,-3
+8,+3
-8,-3
-8,+3
$$x^{2}-5x-24=0$$
So, $$x^{2}-8x + 3x -24=0$$
ie x(x- 8) + 3(x-8) = 0
=> (x+3)(x-8)=0
or x = 8 or -3
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