Instructions

In each of these questions two equations numbered I & II are given. You have to solve both the equations and give answer.

Question 84

I. $$6a^{2}-25a+25=0$$
II. $$15b^{2}-16b+4=0$$

Solution

$$6a^{2}-25a+25=0$$ => $$6a^{2}-10a-15a+25=0$$

=> 2a (3a -5) -5 (3a -5) = 0

So, a = 5/2 or 5/3

$$15b^{2}-16b+4=0$$ => $$15b^{2}-10b -6b+4=0$$

=> 5b (3b-2) - 2(3b - 2) = 0

So, b = 2/5 or 2/3

So, a > b


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