AP ICET 2nd May 2018 Shift-2

Question 84

All the numbers 411, 752 and 1031 leave same remainder 8 whendivided by n. The value of n is

Solution

The given information means that all the following numbers must be divisible by n
411 - 8 = 403
752 - 8 = 744
1031 - 8 = 103 

403 = 13 * 31 
744 = 24 * 31
1023 = 33 * 31
From this, we can say that the only common factor of all three is 31 and hence, n = 31


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