Solution
$$2+x\sqrt{3}$$ = $$\frac{1}{2+\sqrt{3}}$$
Rationalizing the R.H.S.
=> $$2+x\sqrt{3}$$ = $$\frac{1}{2+\sqrt{3}}$$ * $$\frac{2-\sqrt{3}}{2-\sqrt{3}}$$
=> $$2+x\sqrt{3}$$ = $$\frac{2-\sqrt{3}}{4-3}$$
=> $$2+x\sqrt{3}$$ = $$2-\sqrt{3}$$
Comparing both sides, we get $$x$$ = -1
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