If x = 332, y = 332, z = 332, then the value of $$x^3 + y^3 + z^3 - 3xyz$$ is
when x = y = z= 332 , then $$(x^2 + y^2 + z^2 - xy - yz - xz)$$ = 0
and hence $$x^3 + y^3 + z^3 - 3xyz$$ = 0 as $$x^3 + y^3 + z^3 - 3xyz$$ = (x+y+z) $$(x^2 + y^2 + z^2 - xy - yz - xz)$$
and hence the answer for this question is = 0
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