Solution
We see that the number 3240 can be factorised into: $$3240=2^3\times\ 3^4\times\ 5$$
We use the sum of factors formula:
$$\frac{\left(2^{3+1}-1\right)}{2-1}\times\ \frac{\left(3^{4+1}-1\right)}{3-1}\times\ \frac{\left(5^{1+1}-1\right)}{5-1}$$
$$15\times\ 121\times6$$
10890
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